What is the tangent of x^2+y^2+2y=0,(0,-2) ?

The tangent of x^2+y^2+2y=0,(0,-2) is y=-2

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tangent of x^2+y^2+2y=0,(0,-2)

tangent of

x^{2} + y^{2} + 2 y = 0, (0, - 2)

y = - 2

Solution steps

Find the slope of

x^{2} + y^{2} + 2 y = 0 : \frac{d y}{d x} = - \frac{x}{y + 1}

Compute the slope of

x^{2} + y^{2} + 2 y = 0

(0, - 2) : m = 0

Find the line with slope m=

0

and passing through

(0, - 2) : y = - 2

y = - 2

f (x) = 1 + ln (2 x - 1), at x = 1

x^{2} + y^{2} = 25

(23, 2)

y = x^{2} - x^{3} + x, (- 2, 10)

(- 2.4) (7.3)

What is the tangent of x^2+y^2+2y=0,(0,-2) ?
The tangent of x^2+y^2+2y=0,(0,-2) is y=-2