What is the derivative of f(x)=x^2-5 ?

The derivative of f(x)=x^2-5 is 2x

What is the first derivative of f(x)=x^2-5 ?

The first derivative of f(x)=x^2-5 is 2x

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derivative of

f (x) = x^{2} - 5

2 x

Solution steps

\frac{d}{d x} (x^{2} - 5)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (5)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (5) = 0

= 2 x - 0

Simplify

= 2 x

f (x) = \frac{x}{x - 2}

2 e^{2 x}

y = x^{3} ln (x)

y = x^{x}

y = ln (2 x)

What is the derivative of f(x)=x^2-5 ?
The derivative of f(x)=x^2-5 is 2x
What is the first derivative of f(x)=x^2-5 ?
The first derivative of f(x)=x^2-5 is 2x