What is the derivative of f(x)=2x^3+4x ?

The derivative of f(x)=2x^3+4x is 6x^2+4

What is the first derivative of f(x)=2x^3+4x ?

The first derivative of f(x)=2x^3+4x is 6x^2+4

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derivative of

f (x) = 2 x^{3} + 4 x

6 x^{2} + 4

Solution steps

\frac{d}{d x} (2 x^{3} + 4 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{3}) + \frac{d}{d x} (4 x)

\frac{d}{d x} (2 x^{3}) = 6 x^{2}

\frac{d}{d x} (4 x) = 4

= 6 x^{2} + 4

(- 1, 7), (3, - 3)

f (x) = 8 x^{2} + 11 x, at x = 7

3 x - 4 y = 7

(4, - 43)

y = 2 x + 5

What is the derivative of f(x)=2x^3+4x ?
The derivative of f(x)=2x^3+4x is 6x^2+4
What is the first derivative of f(x)=2x^3+4x ?
The first derivative of f(x)=2x^3+4x is 6x^2+4