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Popular >

tangent of y=x^3,(2,8)

Solution

tangent of

y = x^{3}, (2, 8)

Solution

y = 12 x - 16

Solution steps

Find the slope of

y = x^{3} : \frac{d y}{d x} = 3 x^{2}

Compute the slope of

y = x^{3}

at

(2, 8) : m = 12

Find the line with slope m=

12

and passing through

(2, 8) : y = 12 x - 16

y = 12 x - 16

Popular Examples

f = 7

x = 0

derivative of y=ln(x)derivative of

y = ln (x)

slope of y=2x-1 slope

y = 2 x - 1

derivative of y=e^x derivative of

y = e^{x}

Frequently Asked Questions (FAQ)

What is the tangent of y=x^3,(2,8) ?
The tangent of y=x^3,(2,8) is y=12x-16