What is the derivative of f(x)=1+cos(x) ?

The derivative of f(x)=1+cos(x) is -sin(x)

What is the first derivative of f(x)=1+cos(x) ?

The first derivative of f(x)=1+cos(x) is -sin(x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

f (x) = 1 + cos (x)

- sin (x)

Solution steps

\frac{d}{d x} (1 + cos (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) + \frac{d}{d x} (cos (x))

\frac{d}{d x} (1) = 0

\frac{d}{d x} (cos (x)) = - sin (x)

= 0 - sin (x)

Simplify

= - sin (x)

sec^{2} (x)

f = 8

y = x e^{- x}

f (x) = \frac{8}{x}, at x = - 1

y = 10 x^{\frac{4}{5}}

What is the derivative of f(x)=1+cos(x) ?
The derivative of f(x)=1+cos(x) is -sin(x)
What is the first derivative of f(x)=1+cos(x) ?
The first derivative of f(x)=1+cos(x) is -sin(x)