What is the derivative of f(x)= 1/(x+3) ?

The derivative of f(x)= 1/(x+3) is -1/((x+3)^2)

What is the first derivative of f(x)= 1/(x+3) ?

The first derivative of f(x)= 1/(x+3) is -1/((x+3)^2)

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derivative of

f (x) = \frac{1}{x + 3}

- \frac{1}{( x + 3 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{1}{x + 3})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d x} ((x + 3)^{- 1})

Apply the chain rule:

- \frac{1}{( x + 3 ) ^{2}} \frac{d}{d x} (x + 3)

= - \frac{1}{( x + 3 ) ^{2}} \frac{d}{d x} (x + 3)

\frac{d}{d x} (x + 3) = 1

= - \frac{1}{( x + 3 ) ^{2}} \cdot 1

Simplify

= - \frac{1}{( x + 3 ) ^{2}}

y = e^{3 x}

- x^{2}

y = - 1

y = e^{x} + 2 e^{2 x}

(0, 20)

What is the derivative of f(x)= 1/(x+3) ?
The derivative of f(x)= 1/(x+3) is -1/((x+3)^2)
What is the first derivative of f(x)= 1/(x+3) ?
The first derivative of f(x)= 1/(x+3) is -1/((x+3)^2)