What is the derivative of y=(x+1)/(sqrt(x)) ?

The derivative of y=(x+1)/(sqrt(x)) is (x-1)/(2xsqrt(x))

What is the first derivative of y=(x+1)/(sqrt(x)) ?

The first derivative of y=(x+1)/(sqrt(x)) is (x-1)/(2xsqrt(x))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

y = \frac{x + 1}{x}

\frac{x - 1}{2 x x}

Solution steps

\frac{d}{d x} (\frac{x + 1}{x})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x + 1 ) x - \frac{d}{d x} ( x ) ( x + 1 )}{( x ) ^{2}}

\frac{d}{d x} (x + 1) = 1

\frac{d}{d x} (x) = \frac{1}{2 x}

= \frac{1 \cdot x - \frac{1}{2 x} ( x + 1 )}{( x ) ^{2}}

Simplify

\frac{1 \cdot x - \frac{1}{2 x} ( x + 1 )}{( x ) ^{2}} : \frac{x - 1}{2 x x}

= \frac{x - 1}{2 x x}

x^{3} e^{x}

f (x) = \frac{1}{x ^{2} + 1}

(1, 7), (- 2, 3)

\frac{d y}{d x} x^{2} - y^{2} = 16

θ = \frac{5 π}{4}

What is the derivative of y=(x+1)/(sqrt(x)) ?
The derivative of y=(x+1)/(sqrt(x)) is (x-1)/(2xsqrt(x))
What is the first derivative of y=(x+1)/(sqrt(x)) ?
The first derivative of y=(x+1)/(sqrt(x)) is (x-1)/(2xsqrt(x))