What is the derivative of f(x)=x^2-3x+7 ?

The derivative of f(x)=x^2-3x+7 is 2x-3

What is the first derivative of f(x)=x^2-3x+7 ?

The first derivative of f(x)=x^2-3x+7 is 2x-3

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derivative of

f (x) = x^{2} - 3 x + 7

2 x - 3

Solution steps

\frac{d}{d x} (x^{2} - 3 x + 7)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (3 x) + \frac{d}{d x} (7)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (7) = 0

= 2 x - 3 + 0

Simplify

= 2 x - 3

f (x) = cos (x^{2})

f (x) = x x^{2} + 19

f (x) = x

y^{^{'}} x - y = 3

\frac{1}{2}

What is the derivative of f(x)=x^2-3x+7 ?
The derivative of f(x)=x^2-3x+7 is 2x-3
What is the first derivative of f(x)=x^2-3x+7 ?
The first derivative of f(x)=x^2-3x+7 is 2x-3