What is the tangent of f(x)=x^2,\at x=2 ?

The tangent of f(x)=x^2,\at x=2 is y=4x-4

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tangent of f(x)=x^2,\at x=2

tangent of

f (x) = x^{2}, at x = 2

y = 4 x - 4

Solution steps

Find the tangent point:

(2, 4)

Find the slope of

f (x) = x^{2} : \frac{df ( x )}{d x} = 2 x

Compute the slope of

f (x) = x^{2}

x = 2 : m = 4

Find the line with slope m=

4

and passing through

(2, 4) : y = 4 x - 4

y = 4 x - 4

x^{2}

2 x + 3 y = 9

f (x) = x + x

y = - 2

f (x) = 3^{x}

What is the tangent of f(x)=x^2,\at x=2 ?
The tangent of f(x)=x^2,\at x=2 is y=4x-4