What is the tangent of y=x^3-2x^2+5,(2,5) ?

The tangent of y=x^3-2x^2+5,(2,5) is y=4x-3

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tangent of y=x^3-2x^2+5,(2,5)

tangent of

y = x^{3} - 2 x^{2} + 5, (2, 5)

y = 4 x - 3

Solution steps

Find the slope of

y = x^{3} - 2 x^{2} + 5 : \frac{d y}{d x} = 3 x^{2} - 4 x

Compute the slope of

y = x^{3} - 2 x^{2} + 5

(2, 5) : m = 4

Find the line with slope m=

4

and passing through

(2, 5) : y = 4 x - 3

y = 4 x - 3

(5, 8), (- 1, - 4)

x^{2} + (y - 5)^{2} = 25

2 x - 3 y = 6

f (x) = ln (sin^{2} (x))

(- 9, - 6), (5, - 1)

What is the tangent of y=x^3-2x^2+5,(2,5) ?
The tangent of y=x^3-2x^2+5,(2,5) is y=4x-3