What is the slope of 1+ln(2x-1) ?

The slope of 1+ln(2x-1) is 2/(2x-1)

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slope of 1+ln(2x-1)

slope

1 + ln (2 x - 1)

\frac{2}{2 x - 1}

Solution steps

y = 1 + ln (2 x - 1)

In order to find the slope of the function, take the derivative of

1 + ln (2 x - 1)

\frac{d}{d x} (1 + ln (2 x - 1)) = \frac{2}{2 x - 1}

\frac{2}{2 x - 1}

f (m) = m^{2}

y = sin (2 x) + cos^{2} (x)

4 x + 5 y = 31

f (x) = 4 x

f (x) = \frac{2}{x}