What is the general solution for cos(y)=0 ?

The general solution for cos(y)=0 is y= pi/2+2pin,y=(3pi)/2+2pin

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cos(y)=0

cos (y) = 0

y = \frac{π}{2} + 2 πn, y = \frac{3 π}{2} + 2 πn

Degrees

y = 9 0^{\circ} + 36 0^{\circ} n, y = 27 0^{\circ} + 36 0^{\circ} n

Solution steps

cos (y) = 0

General solutions for

cos (y) = 0

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

y = \frac{π}{2} + 2 πn, y = \frac{3 π}{2} + 2 πn

y = \frac{π}{2} + 2 πn, y = \frac{3 π}{2} + 2 πn

2 sin^{2} (x) - 3 sin (x) = - 1

3 cos^{2} (θ) + 2 sin (θ) - 1 = 0

2 sin^{2} (θ) - 3 sin (θ) - 2 = 0

2 cos (x) - 1 = 0

cos (x) = cos (2 x)

What is the general solution for cos(y)=0 ?
The general solution for cos(y)=0 is y= pi/2+2pin,y=(3pi)/2+2pin