What is the general solution for sin(x)-2=cos(x)-2 ?

The general solution for sin(x)-2=cos(x)-2 is x= pi/4+pin

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sin(x)-2=cos(x)-2

sin (x) - 2 = cos (x) - 2

x = \frac{π}{4} + πn

Degrees

x = 4 5^{\circ} + 18 0^{\circ} n

Solution steps

sin (x) - 2 = cos (x) - 2

Subtract

cos (x) - 2

from both sides

sin (x) - cos (x) = 0

Rewrite using trig identities

sin (x) - cos (x) = 0

Divide both sides by

cos (x), cos (x) \neq = 0

\frac{sin ( x ) - cos ( x )}{cos ( x )} = \frac{0}{cos ( x )}

Simplify

\frac{sin ( x )}{cos ( x )} - 1 = 0

Use the basic trigonometric identity:

\frac{sin ( x )}{cos ( x )} = tan (x)

tan (x) - 1 = 0

tan (x) - 1 = 0

Move

1

to the right side

tan (x) - 1 = 0

Add

1

to both sides

tan (x) - 1 + 1 = 0 + 1

Simplify

tan (x) = 1

tan (x) = 1

General solutions for

tan (x) = 1

tan (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

x = \frac{π}{4} + πn

x = \frac{π}{4} + πn

cos (2 θ) + sin^{2} (θ) = 0

tan^{2} (x) + tan (x) = 0, 0 \leq x < 2 π

csc (x) - 1 = 0

cos (2 x) + 5 cos (x) + 3 = 0

2 cos (θ) = 1

What is the general solution for sin(x)-2=cos(x)-2 ?
The general solution for sin(x)-2=cos(x)-2 is x= pi/4+pin