What is the general solution for cos(θ)=0.92 ?

The general solution for cos(θ)=0.92 is θ=0.40271…+2pin,θ=2pi-0.40271…+2pin

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cos(θ)=0.92

cos (θ) = 0.92

θ = 0.40271 \dots + 2 πn, θ = 2 π - 0.40271 \dots + 2 πn

Degrees

θ = 23.07391 \dots^{\circ} + 36 0^{\circ} n, θ = 336.92608 \dots^{\circ} + 36 0^{\circ} n

Solution steps

cos (θ) = 0.92

Apply trig inverse properties

cos (θ) = 0.92

General solutions for

cos (θ) = 0.92

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

θ = arccos (0.92) + 2 πn, θ = 2 π - arccos (0.92) + 2 πn

θ = arccos (0.92) + 2 πn, θ = 2 π - arccos (0.92) + 2 πn

Show solutions in decimal form

θ = 0.40271 \dots + 2 πn, θ = 2 π - 0.40271 \dots + 2 πn

2 sin (2 x) = 1

2 cos (x) = 2

sin (θ) - 1 = 0

sin (2 θ) = 1

(tan (θ) + 1) (sec (θ) - 1) = 0

What is the general solution for cos(θ)=0.92 ?
The general solution for cos(θ)=0.92 is θ=0.40271…+2pin,θ=2pi-0.40271…+2pin