What is the general solution for sec(θ)=(2sqrt(3))/3 ?

The general solution for sec(θ)=(2sqrt(3))/3 is θ= pi/6+2pin,θ=(11pi)/6+2pin

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sec(θ)=(2sqrt(3))/3

sec (θ) = \frac{2 3}{3}

θ = \frac{π}{6} + 2 πn, θ = \frac{11 π}{6} + 2 πn

Degrees

θ = 3 0^{\circ} + 36 0^{\circ} n, θ = 33 0^{\circ} + 36 0^{\circ} n

Solution steps

sec (θ) = \frac{2 3}{3}

General solutions for

sec (θ) = \frac{2 3}{3}

sec (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sec (x) 1 \frac{2 3}{3} 22 Undefined - 2 - 2 - \frac{2 3}{3} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sec (x) - 1 - \frac{2 3}{3} - 2 - 2 Undefined 22 \frac{2 3}{3}

θ = \frac{π}{6} + 2 πn, θ = \frac{11 π}{6} + 2 πn

θ = \frac{π}{6} + 2 πn, θ = \frac{11 π}{6} + 2 πn

sin (x + \frac{π}{4}) - sin (x - \frac{5 π}{4}) = \frac{2}{2}

tan (x) = - \frac{4}{3}

6 sin^{2} (x) = 6 + 3 cos (x)

2 sec (x) - 2 = 0

2 sin^{2} (x) - 7 sin (x) + 3 = 0

What is the general solution for sec(θ)=(2sqrt(3))/3 ?
The general solution for sec(θ)=(2sqrt(3))/3 is θ= pi/6+2pin,θ=(11pi)/6+2pin