What is the general solution for -sin(t)=0 ?

The general solution for -sin(t)=0 is t=2pin,t=pi+2pin

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-sin(t)=0

- sin (t) = 0

t = 2 πn, t = π + 2 πn

Degrees

t = 0^{\circ} + 36 0^{\circ} n, t = 18 0^{\circ} + 36 0^{\circ} n

Solution steps

- sin (t) = 0

Divide both sides by

- 1

- sin (t) = 0

Divide both sides by

- 1

\frac{- sin ( t )}{- 1} = \frac{0}{- 1}

Simplify

sin (t) = 0

sin (t) = 0

General solutions for

sin (t) = 0

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

t = 0 + 2 πn, t = π + 2 πn

t = 0 + 2 πn, t = π + 2 πn

Solve

t = 0 + 2 πn : t = 2 πn

t = 0 + 2 πn

0 + 2 πn = 2 πn

t = 2 πn

t = 2 πn, t = π + 2 πn

cos (x) = 4

tan (x) = \frac{5}{6}

2 cos (θ) = - 3

cos (t) = \frac{3}{2}

(cot (θ) + 1) (sin (θ) + 1) = 0

What is the general solution for -sin(t)=0 ?
The general solution for -sin(t)=0 is t=2pin,t=pi+2pin