What is the general solution for |sin(x)|= 1/2 ?

The general solution for |sin(x)|= 1/2 is x=(7pi)/6+2pin,x=(11pi)/6+2pin,x= pi/6+2pin,x=(5pi)/6+2pin

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|sin(x)|= 1/2

∣ sin (x) ∣ = \frac{1}{2}

x = \frac{7 π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn, x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn

Degrees

x = 21 0^{\circ} + 36 0^{\circ} n, x = 33 0^{\circ} + 36 0^{\circ} n, x = 3 0^{\circ} + 36 0^{\circ} n, x = 15 0^{\circ} + 36 0^{\circ} n

Solution steps

∣ sin (x) ∣ = \frac{1}{2}

Solve by substitution

∣ sin (x) ∣ = \frac{1}{2}

Let:

sin (x) = u

∣ u ∣ = \frac{1}{2}

∣ u ∣ = \frac{1}{2} : u = - \frac{1}{2} or u = \frac{1}{2}

∣ u ∣ = \frac{1}{2}

Apply absolute rule: If

∣ u ∣ = a, a > 0

then

u = a

u = - a

u = - \frac{1}{2} or u = \frac{1}{2}

Substitute back

u = sin (x)

sin (x) = - \frac{1}{2} or sin (x) = \frac{1}{2}

sin (x) = - \frac{1}{2} or sin (x) = \frac{1}{2}

sin (x) = - \frac{1}{2} : x = \frac{7 π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn

sin (x) = - \frac{1}{2}

General solutions for

sin (x) = - \frac{1}{2}

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

x = \frac{7 π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn

x = \frac{7 π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn

sin (x) = \frac{1}{2} : x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn

sin (x) = \frac{1}{2}

General solutions for

sin (x) = \frac{1}{2}

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn

x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn

Combine all the solutions

x = \frac{7 π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn, x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn

sec^{2} (θ) = 2 tan (θ)

2 sin (2 x) + 2 = 0

2 cos^{2} (θ) - 3 sin (θ) + 2 = 0

sin (x) + sin (2 x) + sin (3 x) = 0

sin^{2} (x) - cos^{2} (x) = 1 + cos (x)

What is the general solution for |sin(x)|= 1/2 ?
The general solution for |sin(x)|= 1/2 is x=(7pi)/6+2pin,x=(11pi)/6+2pin,x= pi/6+2pin,x=(5pi)/6+2pin