What is the general solution for sec(2x)-1=0 ?

The general solution for sec(2x)-1=0 is x=pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sec(2x)-1=0

sec (2 x) - 1 = 0

x = πn

Degrees

x = 0^{\circ} + 18 0^{\circ} n

Solution steps

sec (2 x) - 1 = 0

Move

1

to the right side

sec (2 x) - 1 = 0

Add

1

to both sides

sec (2 x) - 1 + 1 = 0 + 1

Simplify

sec (2 x) = 1

sec (2 x) = 1

General solutions for

sec (2 x) = 1

sec (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sec (x) 1 \frac{2 3}{3} 22 Undefined - 2 - 2 - \frac{2 3}{3} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sec (x) - 1 - \frac{2 3}{3} - 2 - 2 Undefined 22 \frac{2 3}{3}

2 x = 0 + 2 πn

2 x = 0 + 2 πn

Solve

2 x = 0 + 2 πn : x = πn

2 x = 0 + 2 πn

0 + 2 πn = 2 πn

2 x = 2 πn

Divide both sides by

2

2 x = 2 πn

Divide both sides by

2

\frac{2 x}{2} = \frac{2 πn}{2}

Simplify

x = πn

x = πn

x = πn

sin (2 x) + sin (x) + 2 cos (x) + 1 = 0

csc (x) = \frac{13}{5}

6 csc (θ) + 7 = 0

cos (2 x) + cos (x) = 0, 0 \leq x \leq 2 π

cos (5 x) cos (3 x) - sin (5 x) sin (3 x) = \frac{3}{2}

What is the general solution for sec(2x)-1=0 ?
The general solution for sec(2x)-1=0 is x=pin