What is the general solution for arctan(2x-8)=-1 ?

The general solution for arctan(2x-8)=-1 is x=-(tan(1))/2+4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

arctan(2x-8)=-1

arctan (2 x - 8) = - 1

x = - \frac{tan ( 1 )}{2} + 4

Solution steps

arctan (2 x - 8) = - 1

Apply trig inverse properties

arctan (2 x - 8) = - 1

arctan (x) = a \Rightarrow x = tan (a)

2 x - 8 = tan (- 1)

tan (- 1) = - tan (1)

tan (- 1)

Use the following property:

tan (- x) = - tan (x)

tan (- 1) = - tan (1)

= - tan (1)

2 x - 8 = - tan (1)

2 x - 8 = - tan (1)

Solve

2 x - 8 = - tan (1) : x = - \frac{tan ( 1 )}{2} + 4

2 x - 8 = - tan (1)

Move

8

to the right side

2 x - 8 = - tan (1)

Add

8

to both sides

2 x - 8 + 8 = - tan (1) + 8

Simplify

2 x = - tan (1) + 8

2 x = - tan (1) + 8

Divide both sides by

2

2 x = - tan (1) + 8

Divide both sides by

2

\frac{2 x}{2} = - \frac{tan ( 1 )}{2} + \frac{8}{2}

Simplify

x = - \frac{tan ( 1 )}{2} + 4

x = - \frac{tan ( 1 )}{2} + 4

x = - \frac{tan ( 1 )}{2} + 4

- 2 cos (2 θ) - 5 = - 4 sin (θ) - 8

3 cos^{2} (θ) - cos (θ) = 0

10 sin^{2} (x) + 11 sin (x) - 8 = 0

2 cos^{2} (x) + 7 cos (x) - 4 = 0

cot (2 θ) = \frac{3}{3}

What is the general solution for arctan(2x-8)=-1 ?
The general solution for arctan(2x-8)=-1 is x=-(tan(1))/2+4