What is the general solution for csc^2(x)+4csc(x)+4=0 ?

The general solution for csc^2(x)+4csc(x)+4=0 is x=(7pi)/6+2pin,x=(11pi)/6+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

csc^2(x)+4csc(x)+4=0

csc^{2} (x) + 4 csc (x) + 4 = 0

x = \frac{7 π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn

Degrees

x = 21 0^{\circ} + 36 0^{\circ} n, x = 33 0^{\circ} + 36 0^{\circ} n

Solution steps

csc^{2} (x) + 4 csc (x) + 4 = 0

Solve by substitution

csc^{2} (x) + 4 csc (x) + 4 = 0

Let:

csc (x) = u

u^{2} + 4 u + 4 = 0

u^{2} + 4 u + 4 = 0 : u = - 2

u^{2} + 4 u + 4 = 0

Solve with the quadratic formula

u^{2} + 4 u + 4 = 0

Quadratic Equation Formula:

For

a = 1, b = 4, c = 4

u_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

u_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot 4 = 0

4^{2} - 4 \cdot 1 \cdot 4

Multiply the numbers:

4 \cdot 1 \cdot 4 = 16

= 4^{2} - 16

4^{2} = 16

= 16 - 16

Subtract the numbers:

16 - 16 = 0

= 0

u_{1, 2} = \frac{- 4 \pm 0}{2 \cdot 1}

u = \frac{- 4}{2 \cdot 1}

\frac{- 4}{2 \cdot 1} = - 2

\frac{- 4}{2 \cdot 1}

Multiply the numbers:

2 \cdot 1 = 2

= \frac{- 4}{2}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{4}{2}

Divide the numbers:

\frac{4}{2} = 2

= - 2

u = - 2

The solution to the quadratic equation is:

u = - 2

Substitute back

u = csc (x)

csc (x) = - 2

csc (x) = - 2

csc (x) = - 2 : x = \frac{7 π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn

csc (x) = - 2

General solutions for

csc (x) = - 2

csc (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} csc (x) Undefiend 22 \frac{2 3}{3} 1 \frac{2 3}{3} 22 x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} csc (x) Undefiend - 2 - 2 - \frac{2 3}{3} - 1 - \frac{2 3}{3} - 2 - 2

x = \frac{7 π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn

x = \frac{7 π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn

Combine all the solutions

x = \frac{7 π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn

6 sin^{2} (x) - cos (x) - 4 = 0

2 sin (2 x) cos (x) + sin (x) = 0

4 cos (x) + 1 = 3

y, x = sin (y)

sin (x) + sin (x) cos (x) = 0

What is the general solution for csc^2(x)+4csc(x)+4=0 ?
The general solution for csc^2(x)+4csc(x)+4=0 is x=(7pi)/6+2pin,x=(11pi)/6+2pin