What is the general solution for sin^2(x)+sin(x)cos(x)=0 ?

The general solution for sin^2(x)+sin(x)cos(x)=0 is x=2pin,x=pi+2pin,x=(3pi)/4+pin

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sin^2(x)+sin(x)cos(x)=0

Solution

sin^{2} (x) + sin (x) cos (x) = 0

Solution

x = 2 πn, x = π + 2 πn, x = \frac{3 π}{4} + πn

Degrees

x = 0^{\circ} + 36 0^{\circ} n, x = 18 0^{\circ} + 36 0^{\circ} n, x = 13 5^{\circ} + 18 0^{\circ} n

Solution steps

sin^{2} (x) + sin (x) cos (x) = 0

Factor

sin^{2} (x) + sin (x) cos (x) : sin (x) (sin (x) + cos (x))

sin^{2} (x) + sin (x) cos (x)

Apply exponent rule:

a^{b + c} = a^{b} a^{c}

sin^{2} (x) = sin (x) sin (x)

= sin (x) sin (x) + sin (x) cos (x)

Factor out common term

sin (x)

= sin (x) (sin (x) + cos (x))

sin (x) (sin (x) + cos (x)) = 0

Solving each part separately

sin (x) = 0 or sin (x) + cos (x) = 0

sin (x) = 0 : x = 2 πn, x = π + 2 πn

sin (x) = 0

General solutions for

sin (x) = 0

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

x = 0 + 2 πn, x = π + 2 πn

x = 0 + 2 πn, x = π + 2 πn

Solve

x = 0 + 2 πn : x = 2 πn

x = 0 + 2 πn

0 + 2 πn = 2 πn

x = 2 πn

x = 2 πn, x = π + 2 πn

sin (x) + cos (x) = 0 : x = \frac{3 π}{4} + πn

sin (x) + cos (x) = 0

Rewrite using trig identities

sin (x) + cos (x) = 0

Divide both sides by

cos (x), cos (x) \neq = 0

\frac{sin ( x ) + cos ( x )}{cos ( x )} = \frac{0}{cos ( x )}

Simplify

\frac{sin ( x )}{cos ( x )} + 1 = 0

Use the basic trigonometric identity:

\frac{sin ( x )}{cos ( x )} = tan (x)

tan (x) + 1 = 0

tan (x) + 1 = 0

Move

1

to the right side

tan (x) + 1 = 0

Subtract

1

from both sides

tan (x) + 1 - 1 = 0 - 1

Simplify

tan (x) = - 1

tan (x) = - 1

General solutions for

tan (x) = - 1

tan (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

x = \frac{3 π}{4} + πn

x = \frac{3 π}{4} + πn

Combine all the solutions

x = 2 πn, x = π + 2 πn, x = \frac{3 π}{4} + πn

Popular Examples

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4 sin (x) + 5 = 4 + sin (x)

9sin(θ)-1=7sin(θ)

9 sin (θ) - 1 = 7 sin (θ)

cot(x)=sin(x)

cot (x) = sin (x)

-sqrt(3)cos(x)-sin(x)=-sqrt(3)

- 3 cos (x) - sin (x) = - 3

9cot^2(x)=3

9 cot^{2} (x) = 3

Frequently Asked Questions (FAQ)

What is the general solution for sin^2(x)+sin(x)cos(x)=0 ?
The general solution for sin^2(x)+sin(x)cos(x)=0 is x=2pin,x=pi+2pin,x=(3pi)/4+pin