What is the general solution for tan(θ)=sqrt(1) ?

The general solution for tan(θ)=sqrt(1) is θ= pi/4+pin

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tan(θ)=sqrt(1)

tan (θ) = 1

θ = \frac{π}{4} + πn

Degrees

θ = 4 5^{\circ} + 18 0^{\circ} n

Solution steps

tan (θ) = 1

Apply rule

1 = 1

tan (θ) = 1

General solutions for

tan (θ) = 1

tan (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

θ = \frac{π}{4} + πn

θ = \frac{π}{4} + πn

sin (2 θ) + cos (2 θ) = 0

5 cot^{2} (x) - 15 = 0

sin (x) = \frac{2}{5}

csc (x) = 5

sec^{2} (x) + tan^{2} (x) - 1 = 0

What is the general solution for tan(θ)=sqrt(1) ?
The general solution for tan(θ)=sqrt(1) is θ= pi/4+pin