What is the general solution for 0.2=cos(2pit) ?

The general solution for 0.2=cos(2pit) is t=(1.36943…)/(2pi)+n,t=1-(1.36943…)/(2pi)+n

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Popular >

0.2=cos(2pit)

Solution

0.2 = cos (2 π t)

Solution

t = \frac{1.36943 \dots}{2 π} + n, t = 1 - \frac{1.36943 \dots}{2 π} + n

Degrees

t = 12.48778 \dots^{\circ}, t = 44.80799 \dots^{\circ}

Solution steps

0.2 = cos (2 π t)

Switch sides

cos (2 π t) = 0.2

Apply trig inverse properties

cos (2 π t) = 0.2

General solutions for

cos (2 π t) = 0.2

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

2 π t = arccos (0.2) + 2 πn, 2 π t = 2 π - arccos (0.2) + 2 πn

2 π t = arccos (0.2) + 2 πn, 2 π t = 2 π - arccos (0.2) + 2 πn

Solve

2 π t = arccos (0.2) + 2 πn : t = \frac{arccos ( 0.2 )}{2 π} + n

2 π t = arccos (0.2) + 2 πn

Divide both sides by

2 π

2 π t = arccos (0.2) + 2 πn

Divide both sides by

2 π

\frac{2 π t}{2 π} = \frac{arccos ( 0.2 )}{2 π} + \frac{2 πn}{2 π}

Simplify

\frac{2 π t}{2 π} = \frac{arccos ( 0.2 )}{2 π} + \frac{2 πn}{2 π}

Simplify

\frac{2 π t}{2 π} : t

\frac{2 π t}{2 π}

Divide the numbers:

\frac{2}{2} = 1

= \frac{π t}{π}

Cancel the common factor:

π

= t

Simplify

\frac{arccos ( 0.2 )}{2 π} + \frac{2 πn}{2 π} : \frac{arccos ( 0.2 )}{2 π} + n

\frac{arccos ( 0.2 )}{2 π} + \frac{2 πn}{2 π}

Cancel

\frac{2 πn}{2 π} : n

\frac{2 πn}{2 π}

Cancel

\frac{2 πn}{2 π} : n

\frac{2 πn}{2 π}

Divide the numbers:

\frac{2}{2} = 1

= \frac{πn}{π}

Cancel the common factor:

π

= n

= n

= \frac{arccos ( 0.2 )}{2 π} + n

t = \frac{arccos ( 0.2 )}{2 π} + n

t = \frac{arccos ( 0.2 )}{2 π} + n

t = \frac{arccos ( 0.2 )}{2 π} + n

Solve

2 π t = 2 π - arccos (0.2) + 2 πn : t = 1 - \frac{arccos ( 0.2 )}{2 π} + n

2 π t = 2 π - arccos (0.2) + 2 πn

Divide both sides by

2 π

2 π t = 2 π - arccos (0.2) + 2 πn

Divide both sides by

2 π

\frac{2 π t}{2 π} = \frac{2 π}{2 π} - \frac{arccos ( 0.2 )}{2 π} + \frac{2 πn}{2 π}

Simplify

\frac{2 π t}{2 π} = \frac{2 π}{2 π} - \frac{arccos ( 0.2 )}{2 π} + \frac{2 πn}{2 π}

Simplify

\frac{2 π t}{2 π} : t

\frac{2 π t}{2 π}

Divide the numbers:

\frac{2}{2} = 1

= \frac{π t}{π}

Cancel the common factor:

π

= t

Simplify

\frac{2 π}{2 π} - \frac{arccos ( 0.2 )}{2 π} + \frac{2 πn}{2 π} : 1 - \frac{arccos ( 0.2 )}{2 π} + n

\frac{2 π}{2 π} - \frac{arccos ( 0.2 )}{2 π} + \frac{2 πn}{2 π}

Apply rule

\frac{a}{a} = 1

\frac{2 π}{2 π} = 1

= 1 - \frac{arccos ( 0.2 )}{2 π} + \frac{2 πn}{2 π}

Cancel

\frac{2 πn}{2 π} : n

\frac{2 πn}{2 π}

Cancel

\frac{2 πn}{2 π} : n

\frac{2 πn}{2 π}

Divide the numbers:

\frac{2}{2} = 1

= \frac{πn}{π}

Cancel the common factor:

π

= n

= n

= 1 - \frac{arccos ( 0.2 )}{2 π} + n

t = 1 - \frac{arccos ( 0.2 )}{2 π} + n

t = 1 - \frac{arccos ( 0.2 )}{2 π} + n

t = 1 - \frac{arccos ( 0.2 )}{2 π} + n

t = \frac{arccos ( 0.2 )}{2 π} + n, t = 1 - \frac{arccos ( 0.2 )}{2 π} + n

Show solutions in decimal form

t = \frac{1.36943 \dots}{2 π} + n, t = 1 - \frac{1.36943 \dots}{2 π} + n

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Frequently Asked Questions (FAQ)

What is the general solution for 0.2=cos(2pit) ?
The general solution for 0.2=cos(2pit) is t=(1.36943…)/(2pi)+n,t=1-(1.36943…)/(2pi)+n