What is the general solution for cos(pi/(60))-cos(pi/(60))=sin(x) ?

The general solution for cos(pi/(60))-cos(pi/(60))=sin(x) is x=2pin,x=pi+2pin

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cos(pi/(60))-cos(pi/(60))=sin(x)

cos (\frac{π}{60}) - cos (\frac{π}{60}) = sin (x)

x = 2 πn, x = π + 2 πn

Degrees

x = 0^{\circ} + 36 0^{\circ} n, x = 18 0^{\circ} + 36 0^{\circ} n

Solution steps

cos (\frac{π}{60}) - cos (\frac{π}{60}) = sin (x)

Switch sides

sin (x) = cos (\frac{π}{60}) - cos (\frac{π}{60})

Add similar elements:

cos (\frac{π}{60}) - cos (\frac{π}{60}) = 0

sin (x) = 0

General solutions for

sin (x) = 0

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

x = 0 + 2 πn, x = π + 2 πn

x = 0 + 2 πn, x = π + 2 πn

Solve

x = 0 + 2 πn : x = 2 πn

x = 0 + 2 πn

0 + 2 πn = 2 πn

x = 2 πn

x = 2 πn, x = π + 2 πn

3 tan^{2} (α) - 3 tan (α) = 0

cos (θ) = - \frac{12}{13}

- tan (x) = 0

3 sin (θ) + 1 = 1

csc^{2} (x) - 3 csc (x) - 4 = 0

What is the general solution for cos(pi/(60))-cos(pi/(60))=sin(x) ?
The general solution for cos(pi/(60))-cos(pi/(60))=sin(x) is x=2pin,x=pi+2pin