What is the general solution for 8sin(θ)-8=4sqrt(3)-8 ?

The general solution for 8sin(θ)-8=4sqrt(3)-8 is θ= pi/3+2pin,θ=(2pi)/3+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

8sin(θ)-8=4sqrt(3)-8

8 sin (θ) - 8 = 43 - 8

θ = \frac{π}{3} + 2 πn, θ = \frac{2 π}{3} + 2 πn

Degrees

θ = 6 0^{\circ} + 36 0^{\circ} n, θ = 12 0^{\circ} + 36 0^{\circ} n

Solution steps

8 sin (θ) - 8 = 43 - 8

Add

8

to both sides

8 sin (θ) - 8 + 8 = 43 - 8 + 8

Simplify

8 sin (θ) = 43

Divide both sides by

8

8 sin (θ) = 43

Divide both sides by

8

\frac{8 sin ( θ )}{8} = \frac{4 3}{8}

Simplify

sin (θ) = \frac{3}{2}

sin (θ) = \frac{3}{2}

General solutions for

sin (θ) = \frac{3}{2}

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

θ = \frac{π}{3} + 2 πn, θ = \frac{2 π}{3} + 2 πn

θ = \frac{π}{3} + 2 πn, θ = \frac{2 π}{3} + 2 πn

sec (θ) = 2 cos (θ)

2 sin^{2} (x) + 3 sin (x) = 0

sin^{2} (x) = - sin (x)

arccos (x) + 2 arcsin (\frac{3}{2}) = π

3 - 3 sin (θ) = 2 cos^{2} (θ)

What is the general solution for 8sin(θ)-8=4sqrt(3)-8 ?
The general solution for 8sin(θ)-8=4sqrt(3)-8 is θ= pi/3+2pin,θ=(2pi)/3+2pin