What is the general solution for sin(θ)=0.21 ?

The general solution for sin(θ)=0.21 is θ=0.21157…+2pin,θ=pi-0.21157…+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sin(θ)=0.21

sin (θ) = 0.21

θ = 0.21157 \dots + 2 πn, θ = π - 0.21157 \dots + 2 πn

Degrees

θ = 12.12235 \dots^{\circ} + 36 0^{\circ} n, θ = 167.87764 \dots^{\circ} + 36 0^{\circ} n

Solution steps

sin (θ) = 0.21

Apply trig inverse properties

sin (θ) = 0.21

General solutions for

sin (θ) = 0.21

sin (x) = a \Rightarrow x = arcsin (a) + 2 πn, x = π - arcsin (a) + 2 πn

θ = arcsin (0.21) + 2 πn, θ = π - arcsin (0.21) + 2 πn

θ = arcsin (0.21) + 2 πn, θ = π - arcsin (0.21) + 2 πn

Show solutions in decimal form

θ = 0.21157 \dots + 2 πn, θ = π - 0.21157 \dots + 2 πn

csc (t) = sec (t)

- 2 sin^{2} (x) = sin (x) - 1

cos (4 θ) - cos (6 θ) = 0

1 - sin (θ) = 0

9 sin^{2} (θ) - 1 = 0

What is the general solution for sin(θ)=0.21 ?
The general solution for sin(θ)=0.21 is θ=0.21157…+2pin,θ=pi-0.21157…+2pin