What is the general solution for tan(θ)+1=2 ?

The general solution for tan(θ)+1=2 is θ= pi/4+pin

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tan(θ)+1=2

tan (θ) + 1 = 2

θ = \frac{π}{4} + πn

Degrees

θ = 4 5^{\circ} + 18 0^{\circ} n

Solution steps

tan (θ) + 1 = 2

Move

1

to the right side

tan (θ) + 1 = 2

Subtract

1

from both sides

tan (θ) + 1 - 1 = 2 - 1

Simplify

tan (θ) = 1

tan (θ) = 1

General solutions for

tan (θ) = 1

tan (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

θ = \frac{π}{4} + πn

θ = \frac{π}{4} + πn

3 sec (θ) + 1 = 7

sin^{2} (x) = cos (x) + 1

tan (x) cos^{2} (x) - tan (x) = 0

3 tan (\frac{1}{2} x) - 1 = 0

cos (x) = \frac{7}{11}

What is the general solution for tan(θ)+1=2 ?
The general solution for tan(θ)+1=2 is θ= pi/4+pin