What is the value of cos(i) ?

The value of cos(i) is (e^2+1)/(2e)

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cos(i)

cos (i)

\frac{e ^{2} + 1}{2 e}

Solution steps

cos (i)

Rewrite using trig identities:

cos (0) cosh (1) - i sin (0) sinh (1)

= cos (0) cosh (1) - i sin (0) sinh (1)

Use the following trivial identity:

sin (0) = 0

= cos (0) cosh (1) - i 0 \cdot sinh (1)

Simplify

= cos (0) cosh (1)

Use the following trivial identity:

cos (0) = 1

Rewrite using trig identities:

cosh (1) = \frac{e ^{2} + 1}{2 e}

= 1 \cdot \frac{e ^{2} + 1}{2 e}

Simplify

= \frac{e ^{2} + 1}{2 e}

sin (6 4^{\circ})

arccos (\frac{3}{2})

4 cos (\frac{π}{2})

cot (1 5^{\circ})

sin (- 7 5^{\circ})