What is the general solution for sin(t)=1 ?

The general solution for sin(t)=1 is t= pi/2+2pin

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sin(t)=1

sin (t) = 1

t = \frac{π}{2} + 2 πn

Degrees

t = 9 0^{\circ} + 36 0^{\circ} n

Solution steps

sin (t) = 1

General solutions for

sin (t) = 1

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

t = \frac{π}{2} + 2 πn

t = \frac{π}{2} + 2 πn

(tan (x) - 1) (3 tan (x) - 1) = 0

\frac{1 - cos ( 2 x )}{sin ( 2 x )} = 3

2 sin (- 3 x - \frac{π}{4}) = 2, 0 \leq x \leq 2 π

9 sin^{2} (θ) - 9 sin (θ) - 2 = - 6 sin (θ)

5 cot (θ) + 3 = 0

What is the general solution for sin(t)=1 ?
The general solution for sin(t)=1 is t= pi/2+2pin