What is the general solution for sin(x)cos(x)-2sin(x)=sin(x) ?

The general solution for sin(x)cos(x)-2sin(x)=sin(x) is x=2pin,x=pi+2pin

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sin(x)cos(x)-2sin(x)=sin(x)

sin (x) cos (x) - 2 sin (x) = sin (x)

x = 2 πn, x = π + 2 πn

Degrees

x = 0^{\circ} + 36 0^{\circ} n, x = 18 0^{\circ} + 36 0^{\circ} n

Solution steps

sin (x) cos (x) - 2 sin (x) = sin (x)

Subtract

sin (x)

from both sides

sin (x) cos (x) - 3 sin (x) = 0

Factor

sin (x) cos (x) - 3 sin (x) : sin (x) (cos (x) - 3)

sin (x) cos (x) - 3 sin (x)

Factor out common term

sin (x)

= sin (x) (cos (x) - 3)

sin (x) (cos (x) - 3) = 0

Solving each part separately

sin (x) = 0 or cos (x) - 3 = 0

sin (x) = 0 : x = 2 πn, x = π + 2 πn

sin (x) = 0

General solutions for

sin (x) = 0

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

x = 0 + 2 πn, x = π + 2 πn

x = 0 + 2 πn, x = π + 2 πn

Solve

x = 0 + 2 πn : x = 2 πn

x = 0 + 2 πn

0 + 2 πn = 2 πn

x = 2 πn

x = 2 πn, x = π + 2 πn

cos (x) - 3 = 0 :

No Solution

cos (x) - 3 = 0

Move

3

to the right side

cos (x) - 3 = 0

Add

3

to both sides

cos (x) - 3 + 3 = 0 + 3

Simplify

cos (x) = 3

cos (x) = 3

- 1 \leq cos (x) \leq 1

No Solution

Combine all the solutions

x = 2 πn, x = π + 2 πn

- 7 sin^{2} (θ) + 2 sin (θ) + 7 = 0

cos (x) - 2 sin^{2} (x) + 1 = 0

3 tan (2 x) + 3 = 0, 0 \leq x < 2 π

sin (2 x) - sin (x) cos (x) = cos (x)

cot^{2} (x) = 1 - csc (x)

What is the general solution for sin(x)cos(x)-2sin(x)=sin(x) ?
The general solution for sin(x)cos(x)-2sin(x)=sin(x) is x=2pin,x=pi+2pin