What is the value of (sin(-20))/(cos(380))+tan(200) ?

The value of (sin(-20))/(cos(380))+tan(200) is 0

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(sin(-20))/(cos(380))+tan(200)

\frac{sin ( - 2 0 ^{\circ} )}{cos ( 38 0 ^{\circ} )} + tan (20 0^{\circ})

0

Solution steps

\frac{sin ( - 2 0 ^{\circ} )}{cos ( 38 0 ^{\circ} )} + tan (20 0^{\circ})

Simplify

= \frac{sin ( - 2 0 ^{\circ} ) + tan ( 20 0 ^{\circ} ) cos ( 38 0 ^{\circ} )}{cos ( 38 0 ^{\circ} )}

Use the following property:

sin (- x) = - sin (x)

sin (- 2 0^{\circ}) = - sin (2 0^{\circ})

= \frac{- sin ( 2 0 ^{\circ} ) + tan ( 20 0 ^{\circ} ) cos ( 38 0 ^{\circ} )}{cos ( 38 0 ^{\circ} )}

tan (20 0^{\circ}) = tan (2 0^{\circ})

= \frac{- sin ( 2 0 ^{\circ} ) + tan ( 2 0 ^{\circ} ) cos ( 38 0 ^{\circ} )}{cos ( 38 0 ^{\circ} )}

cos (38 0^{\circ}) = cos (2 0^{\circ})

= \frac{- sin ( 2 0 ^{\circ} ) + tan ( 2 0 ^{\circ} ) cos ( 2 0 ^{\circ} )}{cos ( 38 0 ^{\circ} )}

cos (38 0^{\circ}) = cos (2 0^{\circ})

= \frac{- sin ( 2 0 ^{\circ} ) + tan ( 2 0 ^{\circ} ) cos ( 2 0 ^{\circ} )}{cos ( 2 0 ^{\circ} )}

Rewrite using trig identities:

tan (2 0^{\circ}) = \frac{sin ( 2 0 ^{\circ} )}{cos ( 2 0 ^{\circ} )}

= \frac{- sin ( 2 0 ^{\circ} ) + \frac{s i n ( 2 0 ^{\circ} )}{c o s ( 2 0 ^{\circ} )} cos ( 2 0 ^{\circ} )}{cos ( 2 0 ^{\circ} )}

Simplify

= 0

cot (- \frac{4 π}{3})

cos (0.3)

arctan (\frac{5}{1})

tan (\frac{π}{3} + \frac{π}{4})

sin (3 0^{\circ} + 4 5^{\circ})

What is the value of (sin(-20))/(cos(380))+tan(200) ?
The value of (sin(-20))/(cos(380))+tan(200) is 0