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Popular >

tan(225)

Solution

tan (22 5^{\circ})

Solution

1

Solution steps

tan (22 5^{\circ})

tan (22 5^{\circ}) = tan (4 5^{\circ})

tan (22 5^{\circ})

Rewrite

22 5^{\circ}

as

18 0^{\circ} + 4 5^{\circ}

= tan (18 0^{\circ} + 4 5^{\circ})

Apply the periodicity of

tan

:

tan (x + 18 0^{\circ}) = tan (x)

tan (18 0^{\circ} + 4 5^{\circ}) = tan (4 5^{\circ})

= tan (4 5^{\circ})

= tan (4 5^{\circ})

Use the following trivial identity:

tan (4 5^{\circ}) = 1

tan (4 5^{\circ})

tan (x)

periodicity table with

18 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

= 1

= 1

Popular Examples

tan (30 0^{\circ})

cos (- \frac{5 π}{6})

2 tan^{2} (x) - 2 = 0

cos (2 x) = - \frac{1}{2}

cos (x) = 5

Frequently Asked Questions (FAQ)

What is the value of tan(225) ?
The value of tan(225) is 1