What is the value of cot(600) ?

The value of cot(600) is (sqrt(3))/3

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cot(600)

cot (60 0^{\circ})

\frac{3}{3}

Decimal Notation

0.57735 \dots

Solution steps

cot (60 0^{\circ})

cot (60 0^{\circ}) = cot (6 0^{\circ})

cot (60 0^{\circ})

Rewrite

60 0^{\circ}

18 0^{\circ} \cdot 3 + 6 0^{\circ}

= cot (18 0^{\circ} 3 + 6 0^{\circ})

Apply the periodicity of

cot

cot (x + 18 0^{\circ} \cdot k) = cot (x)

cot (18 0^{\circ} \cdot 3 + 6 0^{\circ}) = cot (6 0^{\circ})

= cot (6 0^{\circ})

= cot (6 0^{\circ})

Use the following trivial identity:

cot (6 0^{\circ}) = \frac{3}{3}

cot (6 0^{\circ})

cot (x)

periodicity table with

18 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} cot (x) \mp \infty 31 \frac{3}{3} 0 - \frac{3}{3} - 1 - 3

= \frac{3}{3}

= \frac{3}{3}

cot (\frac{1}{2})

sec^{2} (- \frac{π}{3})

tan (48 0^{\circ})

cosh (6)

3 cos (\frac{5 π}{12})