What is the value of 6tan(45)-8cos(60) ?

The value of 6tan(45)-8cos(60) is 2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

6tan(45)-8cos(60)

6 tan (4 5^{\circ}) - 8 cos (6 0^{\circ})

2

Solution steps

6 tan (4 5^{\circ}) - 8 cos (6 0^{\circ})

Use the following trivial identity:

tan (4 5^{\circ}) = 1

tan (4 5^{\circ})

tan (x)

periodicity table with

18 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

= 1

Use the following trivial identity:

cos (6 0^{\circ}) = \frac{1}{2}

cos (6 0^{\circ})

cos (x)

periodicity table with

36 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= \frac{1}{2}

= 6 \cdot 1 - 8 \cdot \frac{1}{2}

Simplify

6 \cdot 1 - 8 \cdot \frac{1}{2} : 2

6 \cdot 1 - 8 \cdot \frac{1}{2}

6 \cdot 1 = 6

6 \cdot 1

Multiply the numbers:

6 \cdot 1 = 6

= 6

8 \cdot \frac{1}{2} = 4

8 \cdot \frac{1}{2}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 8}{2}

Multiply the numbers:

1 \cdot 8 = 8

= \frac{8}{2}

Divide the numbers:

\frac{8}{2} = 4

= 4

= 6 - 4

Subtract the numbers:

6 - 4 = 2

= 2

= 2

csc (\frac{37 π}{12})

sin (112 5^{\circ})

\frac{sin ( 1.047 )}{sin ( 0.524 )}

1 - cos^{2} (3 0^{\circ}) - cos^{2} (6 0^{\circ})

ln (sech (0))