What is the value of arcsin(cos(300)) ?

The value of arcsin(cos(300)) is pi/6

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arcsin(cos(300))

arcsin (cos (30 0^{\circ}))

\frac{π}{6}

Decimal Notation

30

Solution steps

arcsin (cos (30 0^{\circ}))

Rewrite using trig identities:

cos (30 0^{\circ}) = sin (- 21 0^{\circ})

cos (30 0^{\circ})

sin (9 0^{\circ} - x) = cos (x)

= sin (9 0^{\circ} - 30 0^{\circ})

= sin (- 21 0^{\circ})

= arcsin (sin (- 21 0^{\circ}))

Use the inverse trig property:

3 0^{\circ}

arcsin (sin (- 21 0^{\circ}))

For

- 9 0^{\circ} \leq x \leq 9 0^{\circ}, a rcs in (s in (x)) = x

Rewrite using trig identities:

sin (- 21 0^{\circ}) = sin (3 0^{\circ})

sin (- 21 0^{\circ})

sin (x) = sin (18 0^{\circ} - (x))

= sin (21 0^{\circ} - 18 0^{\circ})

= sin (3 0^{\circ})

= arcsin (sin (3 0^{\circ}))

- 9 0^{\circ} \leq 3 0^{\circ} \leq 9 0^{\circ}

= 3 0^{\circ}

= 3 0^{\circ}

arcsin (\frac{2}{2.5})

cos (3 0^{\circ}) tan (3 0^{\circ})

cot (- 75 0^{\circ})

2 cos (\frac{3}{4} π)

\frac{sin ( 3 0 ^{\circ} ) - sec ( 6 0 ^{\circ} )}{sin ( 3 0 ^{\circ} ) + cos ( 6 0 ^{\circ} )}