What is the value of (-1)-arctan(-1) ?

The value of (-1)-arctan(-1) is -1+pi/4

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(-1)-arctan(-1)

(- 1) - arctan (- 1)

- 1 + \frac{π}{4}

Decimal Notation

- 12.3

Solution steps

(- 1) - arctan (- 1)

= - 1 - arctan (- 1)

Rewrite using trig identities:

arctan (- 1) = - \frac{π}{4}

arctan (- 1)

Use the following property:

arctan (- x) = - arctan (x)

arctan (- 1) = - arctan (1)

= - arctan (1)

Use the following trivial identity:

arctan (1) = \frac{π}{4}

arctan (1)

x 0 \frac{3}{3} 13 arctan (x) 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} arctan (x) 0^{\circ} 3 0^{\circ} 4 5^{\circ} 6 0^{\circ}

= \frac{π}{4}

= - \frac{π}{4}

= - 1 - (- \frac{π}{4})

Simplify

= - 1 + \frac{π}{4}

cos (30 π)

8 \cdot sin (2 4^{\circ})

ln ∣ 4 + tan (0) ∣

ln ∣ sec (0) + tan (0) ∣

cos (- \frac{1}{5})