What is the value of sin((2pi)/2)+cos((2pi)/2) ?

The value of sin((2pi)/2)+cos((2pi)/2) is -1

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sin((2pi)/2)+cos((2pi)/2)

sin (\frac{2 π}{2}) + cos (\frac{2 π}{2})

- 1

Solution steps

sin (\frac{2 π}{2}) + cos (\frac{2 π}{2})

Simplify

= sin (π) + cos (π)

Use the following trivial identity:

sin (π) = 0

sin (π)

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= 0

Use the following trivial identity:

cos (π) = (- 1)

cos (π)

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= (- 1)

= 0 - 1

Simplify

= - 1

cos (5.5)

- 51.875 cos (\frac{2 π}{365} (55 - 354)) + 727.725

(cot (1 0^{\circ}) - cot (8 0^{\circ})) tan (2 0^{\circ})

cos (\frac{17 π}{6}) \cdot sec (- 6 0^{\circ}) + cot (21 0^{\circ})

sec (\frac{19 π}{3})

What is the value of sin((2pi)/2)+cos((2pi)/2) ?
The value of sin((2pi)/2)+cos((2pi)/2) is -1