What is the value of tan(pi/3-pi/4) ?

The value of tan(pi/3-pi/4) is 2-sqrt(3)

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tan(pi/3-pi/4)

Solution

tan (\frac{π}{3} - \frac{π}{4})

Solution

2 - 3

Decimal Notation

0.26794 \dots

Solution steps

tan (\frac{π}{3} - \frac{π}{4})

Rewrite using trig identities:

\frac{tan ( \frac{π}{3} ) - tan ( \frac{π}{4} )}{1 + tan ( \frac{π}{3} ) tan ( \frac{π}{4} )}

tan (\frac{π}{3} - \frac{π}{4})

Use the Angle Difference identity:

tan (s - t) = \frac{tan ( s ) - tan ( t )}{1 + tan ( s ) tan ( t )}

= \frac{tan ( \frac{π}{3} ) - tan ( \frac{π}{4} )}{1 + tan ( \frac{π}{3} ) tan ( \frac{π}{4} )}

= \frac{tan ( \frac{π}{3} ) - tan ( \frac{π}{4} )}{1 + tan ( \frac{π}{3} ) tan ( \frac{π}{4} )}

Use the following trivial identity:

tan (\frac{π}{3}) = 3

tan (\frac{π}{3})

tan (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

= 3

Use the following trivial identity:

tan (\frac{π}{4}) = 1

tan (\frac{π}{4})

tan (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

= 1

= \frac{3 - 1}{1 + 3 \cdot 1}

Simplify

\frac{3 - 1}{1 + 3 \cdot 1} : 2 - 3

\frac{3 - 1}{1 + 3 \cdot 1}

Multiply:

3 \cdot 1 = 3

= \frac{3 - 1}{1 + 3}

Rationalize

\frac{3 - 1}{1 + 3} : 2 - 3

\frac{3 - 1}{1 + 3}

Multiply by the conjugate

\frac{1 - 3}{1 - 3}

= \frac{( 3 - 1 ) ( 1 - 3 )}{( 1 + 3 ) ( 1 - 3 )}

(3 - 1) (1 - 3) = 23 - 4

(3 - 1) (1 - 3)

Apply FOIL method:

(a + b) (c + d) = a c + a d + b c + b d

a = 3, b = - 1, c = 1, d = - 3

= 3 \cdot 1 + 3 (- 3) + (- 1) \cdot 1 + (- 1) (- 3)

Apply minus-plus rules

+ (- a) = - a, (- a) (- b) = ab

= 1 \cdot 3 - 33 - 1 \cdot 1 + 1 \cdot 3

Simplify

1 \cdot 3 - 33 - 1 \cdot 1 + 1 \cdot 3 : 23 - 4

1 \cdot 3 - 33 - 1 \cdot 1 + 1 \cdot 3

Add similar elements:

1 \cdot 3 + 1 \cdot 3 = 23

= 23 - 33 - 1 \cdot 1

Apply radical rule:

a a = a

33 = 3

= 23 - 3 - 1 \cdot 1

Multiply the numbers:

1 \cdot 1 = 1

= 23 - 3 - 1

Subtract the numbers:

- 3 - 1 = - 4

= 23 - 4

= 23 - 4

(1 + 3) (1 - 3) = - 2

(1 + 3) (1 - 3)

Apply Difference of Two Squares Formula:

(a + b) (a - b) = a^{2} - b^{2}

a = 1, b = 3

= 1^{2} - (3)^{2}

Simplify

1^{2} - (3)^{2} : - 2

1^{2} - (3)^{2}

Apply rule

1^{a} = 1

1^{2} = 1

= 1 - (3)^{2}

(3)^{2} = 3

(3)^{2}

Apply radical rule:

a = a^{\frac{1}{2}}

= (3^{\frac{1}{2}})^{2}

Apply exponent rule:

(a^{b})^{c} = a^{b c}

= 3^{\frac{1}{2} \cdot 2}

\frac{1}{2} \cdot 2 = 1

\frac{1}{2} \cdot 2

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2}{2}

Cancel the common factor:

2

= 1

= 3

= 1 - 3

Subtract the numbers:

1 - 3 = - 2

= - 2

= - 2

= \frac{2 3 - 4}{- 2}

Apply the fraction rule:

\frac{- a}{- b} = \frac{a}{b}

23 - 4 = - (4 - 23)

= \frac{4 - 2 3}{2}

Factor

4 - 23 : 2 (2 - 3)

4 - 23

Rewrite as

= 2 \cdot 2 - 23

Factor out common term

2

= 2 (2 - 3)

= \frac{2 ( 2 - 3 )}{2}

Divide the numbers:

\frac{2}{2} = 1

= 2 - 3

= 2 - 3

= 2 - 3

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0+cos(0)

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arctan (\frac{17}{12})

Frequently Asked Questions (FAQ)

What is the value of tan(pi/3-pi/4) ?
The value of tan(pi/3-pi/4) is 2-sqrt(3)