What is the value of -sin(2(pi/4)) ?

The value of -sin(2(pi/4)) is -1

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-sin(2(pi/4))

- sin (2 (\frac{π}{4}))

- 1

Solution steps

- sin (2 (\frac{π}{4}))

= - sin (2 \cdot \frac{π}{4})

Rewrite using trig identities:

sin (2 \cdot \frac{π}{4}) = 1

sin (2 \cdot \frac{π}{4})

Simplify:

2 \cdot \frac{π}{4} = \frac{π}{2}

2 \cdot \frac{π}{4}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{π 2}{4}

Cancel the common factor:

2

= \frac{π}{2}

= sin (\frac{π}{2})

Use the following trivial identity:

sin (\frac{π}{2}) = 1

sin (\frac{π}{2})

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= 1

= 1

= - 1

arccot (- 6)

sin (\frac{π}{2} 4)

sin (3 0^{\circ}) \cdot 100

arcsech (1)

arccos (- \frac{6}{10})