What is the value of -sin(-60) ?

The value of -sin(-60) is (sqrt(3))/2

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-sin(-60)

- sin (- 6 0^{\circ})

\frac{3}{2}

Decimal Notation

0.86602 \dots

Solution steps

- sin (- 6 0^{\circ})

Rewrite using trig identities:

sin (- 6 0^{\circ}) = - \frac{3}{2}

sin (- 6 0^{\circ})

Use the following property:

sin (- x) = - sin (x)

sin (- 6 0^{\circ}) = - sin (6 0^{\circ})

= - sin (6 0^{\circ})

Use the following trivial identity:

sin (6 0^{\circ}) = \frac{3}{2}

sin (6 0^{\circ})

sin (x)

periodicity table with

36 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= \frac{3}{2}

= - \frac{3}{2}

= - (- \frac{3}{2})

Simplify

= \frac{3}{2}

arctan (- 1.841)

26 cos (4 5^{\circ})

csc (arcsec (- 25))

cos (arctan (- \frac{2}{9}))

20 sin (8 0^{\circ})