What is the value of (-tan^2(0))/(1-cos(0)) ?

The value of (-tan^2(0))/(1-cos(0)) is Undefined

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(-tan^2(0))/(1-cos(0))

\frac{- tan ^{2} ( 0 )}{1 - cos ( 0 )}

Undefined

Solution steps

\frac{- tan ^{2} ( 0 )}{1 - cos ( 0 )}

Use the following trivial identity:

tan (0) = 0

tan (0)

tan (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

= 0

Use the following trivial identity:

cos (0) = 1

cos (0)

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= 1

= \frac{- 0 ^{2}}{1 - 1}

= Undefined

cos (\frac{π}{2} \cdot 4)

3 0^{\circ} + cos (6 0^{\circ})

\frac{15}{tan ( 7 0 ^{\circ} )}

5 \cdot sin (3 7^{\circ})

sin (40.5 4^{\circ})

What is the value of (-tan^2(0))/(1-cos(0)) ?
The value of (-tan^2(0))/(1-cos(0)) is Undefined