What is the value of cos(arccot(4/5)-arcsin(-4/5)) ?

The value of cos(arccot(4/5)-arcsin(-4/5)) is cos(arccot(4/5)+arcsin(4/5))

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cos(arccot(4/5)-arcsin(-4/5))

cos (arccot (\frac{4}{5}) - arcsin (- \frac{4}{5}))

cos (arccot (\frac{4}{5}) + arcsin (\frac{4}{5}))

Decimal Notation

- 0.24987 \dots

Solution steps

cos (arccot (\frac{4}{5}) - arcsin (- \frac{4}{5}))

Use the following property:

arcsin (- x) = - arcsin (x)

arcsin (- \frac{4}{5}) = - arcsin (\frac{4}{5})

= cos (arccot (\frac{4}{5}) - (- arcsin (\frac{4}{5})))

= cos (arccot (\frac{4}{5}) + arcsin (\frac{4}{5}))

arcsin (0.18)

arcsin (0.14)

cos (2 π^{3})

arcsin (0.06)

arcsin (0.08)

What is the value of cos(arccot(4/5)-arcsin(-4/5)) ?
The value of cos(arccot(4/5)-arcsin(-4/5)) is cos(arccot(4/5)+arcsin(4/5))