What is the value of 15sin(120) ?

The value of 15sin(120) is (15sqrt(3))/2

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15sin(120)

15 sin (12 0^{\circ})

\frac{15 3}{2}

Decimal Notation

12.99038 \dots

Solution steps

15 sin (12 0^{\circ})

Use the following trivial identity:

sin (12 0^{\circ}) = \frac{3}{2}

sin (12 0^{\circ})

sin (x)

periodicity table with

36 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= \frac{3}{2}

= 15 \cdot \frac{3}{2}

Simplify

15 \cdot \frac{3}{2} : \frac{15 3}{2}

15 \cdot \frac{3}{2}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{3 \cdot 15}{2}

= \frac{15 3}{2}

sin (2 0^{\circ}) \cdot cos (2 0^{\circ})

sin^{2} (\frac{5 π}{12})

cos (\frac{π}{2})

\frac{784}{2 ( sin ( 1 0 ^{\circ} ) )}

cos (π (- 8.3 - 5.4)) + sin (π (8.3 - 5.4))