What is the value of 2.8*cos(60) ?

The value of 2.8*cos(60) is 7/5

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2.8*cos(60)

2.8 \cdot cos (6 0^{\circ})

\frac{7}{5}

Decimal Notation

1.4

Solution steps

2.8 cos (6 0^{\circ})

= \frac{14}{5} cos (6 0^{\circ})

Use the following trivial identity:

cos (6 0^{\circ}) = \frac{1}{2}

cos (6 0^{\circ})

cos (x)

periodicity table with

36 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= \frac{1}{2}

= \frac{14}{5} \cdot \frac{1}{2}

Simplify

\frac{14}{5} \cdot \frac{1}{2} : \frac{7}{5}

\frac{14}{5} \cdot \frac{1}{2}

Cross-cancel common factor:

2

= \frac{7}{5}

= \frac{7}{5}

arctan (\frac{- 3 3}{- 3})

sin^{2} (\frac{3 π}{4}) + cos^{2} (\frac{3 π}{4})

2 sin (2 π) + 3 cos (2 π)

\frac{sec ( 33 0 ^{\circ} )}{cot ( 21 0 ^{\circ} )}

\frac{7 sin ( 0.001 )}{( 0.001 )}