What is the value of (sin(45))/(1.41) ?

The value of (sin(45))/(1.41) is (50sqrt(2))/(141)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(sin(45))/(1.41)

\frac{sin ( 4 5 ^{\circ} )}{1.41}

\frac{50 2}{141}

Decimal Notation

0.50149 \dots

Solution steps

\frac{sin ( 4 5 ^{\circ} )}{1.41}

= \frac{sin ( 4 5 ^{\circ} )}{\frac{141}{100}}

Use the following trivial identity:

sin (4 5^{\circ}) = \frac{2}{2}

sin (4 5^{\circ})

sin (x)

periodicity table with

36 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= \frac{2}{2}

= \frac{\frac{2}{2}}{\frac{141}{100}}

Simplify

\frac{\frac{2}{2}}{\frac{141}{100}} : \frac{50 2}{141}

\frac{\frac{2}{2}}{\frac{141}{100}}

Divide fractions:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{2 \cdot 100}{2 \cdot 141}

Multiply the numbers:

2 \cdot 141 = 282

= \frac{100 2}{282}

Cancel the common factor:

2

= \frac{50 2}{141}

= \frac{50 2}{141}

tanh (ln (3)) - tanh (0)

cos^{2} (0.6)

cos (4 0^{\circ}) \cdot 8

13 cos (5 4^{\circ})

- cos (\frac{π}{8})

What is the value of (sin(45))/(1.41) ?
The value of (sin(45))/(1.41) is (50sqrt(2))/(141)