What is the value of 2.4*sin(30) ?

The value of 2.4*sin(30) is 6/5

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2.4*sin(30)

2.4 \cdot sin (3 0^{\circ})

\frac{6}{5}

Decimal Notation

1.2

Solution steps

2.4 sin (3 0^{\circ})

= \frac{12}{5} sin (3 0^{\circ})

Use the following trivial identity:

sin (3 0^{\circ}) = \frac{1}{2}

sin (3 0^{\circ})

sin (x)

periodicity table with

36 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= \frac{1}{2}

= \frac{12}{5} \cdot \frac{1}{2}

Simplify

\frac{12}{5} \cdot \frac{1}{2} : \frac{6}{5}

\frac{12}{5} \cdot \frac{1}{2}

Cross-cancel common factor:

2

= \frac{6}{5}

= \frac{6}{5}

sin (15 0^{\circ}) + cos (51 0^{\circ}) + tan (411 0^{\circ}) - tan (21 0^{\circ})

tan (\frac{\frac{3}{2}}{- \frac{1}{2}})

sin^{4} (\frac{π}{3})

sin^{2} (3 0^{\circ}) - cot^{2} (6 0^{\circ})

1 + 2 cos (6 0^{\circ})