What is the value of sin(42)cos(12)-cos(42)sin(12) ?

The value of sin(42)cos(12)-cos(42)sin(12) is 1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sin(42)cos(12)-cos(42)sin(12)

sin (4 2^{\circ}) cos (1 2^{\circ}) - cos (4 2^{\circ}) sin (1 2^{\circ})

\frac{1}{2}

Decimal Notation

0.5

Solution steps

sin (4 2^{\circ}) cos (1 2^{\circ}) - cos (4 2^{\circ}) sin (1 2^{\circ})

Rewrite using trig identities:

sin (3 0^{\circ})

sin (4 2^{\circ}) cos (1 2^{\circ}) - cos (4 2^{\circ}) sin (1 2^{\circ})

Use the Angle Difference identity:

sin (s) cos (t) - cos (s) sin (t) = sin (s - t)

= sin (4 2^{\circ} - 1 2^{\circ})

Simplify

= sin (3 0^{\circ})

= sin (3 0^{\circ})

Use the following trivial identity:

sin (3 0^{\circ}) = \frac{1}{2}

sin (3 0^{\circ})

sin (x)

periodicity table with

36 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= \frac{1}{2}

= \frac{1}{2}

9.81 \cdot cos (3 0^{\circ})

50 arcsin (\frac{21}{5}) - 421

2 cos (6 0^{\circ}) + 4 tan (3 7^{\circ}) - sec^{2} (4 5^{\circ})

sin (26. 1^{\circ})

- csc (\frac{5 π}{3})

What is the value of sin(42)cos(12)-cos(42)sin(12) ?
The value of sin(42)cos(12)-cos(42)sin(12) is 1/2