What is the value of (100^2sin(60))/(9.8) ?

The value of (100^2sin(60))/(9.8) is (25000sqrt(3))/(49)

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(100^2sin(60))/(9.8)

\frac{10 0 ^{2} sin ( 6 0 ^{\circ} )}{9.8}

\frac{25000 3}{49}

Decimal Notation

883.69939 \dots

Solution steps

\frac{10 0 ^{2} sin ( 6 0 ^{\circ} )}{9.8}

= \frac{10 0 ^{2} sin ( 6 0 ^{\circ} )}{\frac{49}{5}}

Use the following trivial identity:

sin (6 0^{\circ}) = \frac{3}{2}

sin (6 0^{\circ})

sin (x)

periodicity table with

36 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= \frac{3}{2}

= \frac{10 0 ^{2} \cdot \frac{3}{2}}{\frac{49}{5}}

Simplify

\frac{10 0 ^{2} \cdot \frac{3}{2}}{\frac{49}{5}} : \frac{25000 3}{49}

\frac{10 0 ^{2} \cdot \frac{3}{2}}{\frac{49}{5}}

Apply the fraction rule:

\frac{a}{\frac{b}{c}} = \frac{a \cdot c}{b}

= \frac{10 0 ^{2} \cdot \frac{3}{2} \cdot 5}{49}

10 0^{2} \cdot \frac{3}{2} \cdot 5 = 50000 \cdot \frac{3}{2}

10 0^{2} \cdot \frac{3}{2} \cdot 5

10 0^{2} = 10000

= 10000 \cdot 5 \cdot \frac{3}{2}

Multiply the numbers:

10000 \cdot 5 = 50000

= 50000 \cdot \frac{3}{2}

= \frac{50000 \cdot \frac{3}{2}}{49}

Multiply

50000 \cdot \frac{3}{2} : 250003

50000 \cdot \frac{3}{2}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{3 \cdot 50000}{2}

Divide the numbers:

\frac{50000}{2} = 25000

= 250003

= \frac{25000 3}{49}

= \frac{25000 3}{49}

arctan (0.8718)

50 cos (5 2^{\circ})

\frac{1}{4 6} arctan (\frac{2}{3} tan (2 π))

sin (\frac{π}{3}) + cos^{2} (\frac{5 π}{6})

1.5 \cdot sin (0.14)

What is the value of (100^2sin(60))/(9.8) ?
The value of (100^2sin(60))/(9.8) is (25000sqrt(3))/(49)