What is the value of cos((10pi)/(12)) ?

The value of cos((10pi)/(12)) is -(sqrt(3))/2

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cos((10pi)/(12))

cos (\frac{10 π}{12})

- \frac{3}{2}

Decimal Notation

- 0.86602 \dots

Solution steps

cos (\frac{10 π}{12})

Simplify:

\frac{10 π}{12} = \frac{5 π}{6}

\frac{10 π}{12}

Cancel the common factor:

2

= \frac{5 π}{6}

= cos (\frac{5 π}{6})

Use the following trivial identity:

cos (\frac{5 π}{6}) = - \frac{3}{2}

cos (\frac{5 π}{6})

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= - \frac{3}{2}

= - \frac{3}{2}

csc (3 0^{\circ}) - cot (4 5^{\circ})

arctan (\frac{30}{10})

arctan (\frac{24.5}{20})

6 sin (5.5)

arccos (\frac{- 2}{2 21})

What is the value of cos((10pi)/(12)) ?
The value of cos((10pi)/(12)) is -(sqrt(3))/2