What is the value of -sin(0)+ln(3)*3^{(0)+2} ?

The value of -sin(0)+ln(3)*3^{(0)+2} is 9ln(3)

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-sin(0)+ln(3)*3^{(0)+2}

- sin (0) + ln (3) \cdot 3^{(0) + 2}

9 ln (3)

Decimal Notation

9.88751 \dots

Solution steps

- sin (0) + ln (3) \cdot 3^{(0) + 2}

= - sin (0) + ln (3) \cdot 3^{0 + 2}

Use the following trivial identity:

sin (0) = 0

sin (0)

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= 0

= - 0 + ln (3) \cdot 3^{0 + 2}

Simplify

= 9 ln (3)

arctan (\frac{5.9}{112})

10 sin (2)

sinh (\frac{πi}{2})

sin (\frac{29 π}{4})

cos ((\frac{3 π}{4}) + (\frac{5 π}{3}))

What is the value of -sin(0)+ln(3)*3^{(0)+2} ?
The value of -sin(0)+ln(3)*3^{(0)+2} is 9ln(3)